11t^2-1.2t-1.2=0

Solution for 11t^2-1.2t-1.2=0 equation:

11t^2-1.2t-1.2=0

a = 11; b = -1.2; c = -1.2;
Δ = b2-4ac
Δ = -1.22-4·11·(-1.2)
Δ = 54.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.2)-\sqrt{54.24}}{2*11}=\frac{1.2-\sqrt{54.24}}{22}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.2)+\sqrt{54.24}}{2*11}=\frac{1.2+\sqrt{54.24}}{22}
$